Quick Overview
One range nests inside another when its `min` is no lower and its `max` no higher. Comparing those two boundaries is a single `O(n)` pass; sorting first is unnecessary.
### 1. The Challenge: Boundary Nesting Test Create a function `can_nest(list1, list2)` that returns `True` if `list1` can be nested inside `list2`, and `False` otherwise. `list1` can be nested inside `list2` if and only if: 1. `min(list1)` is strictly greater than `min(list2)`. 2. `max(list1)` is strictly less than `max(list2)`. ### 2. Why It Matters Boundary nesting tests compare ranges and datasets to verify subset constraints, container fitting, and bounding box collisions. ### 3. The Python Solution Compare boundary conditions using `min()` and `max()`: ```python def can_nest(list1, list2): return min(list1) > min(list2) and max(list1) < max(list2) # Testing our function print(can_nest([1, 2, 3, 4], [0, 6])) # Output: True (1 > 0 and 4 < 6) print(can_nest([3, 1], [4, 0])) # Output: True (1 > 0 and 3 < 4) print(can_nest([9, 9, 8], [8, 9])) # Output: False (9 is not < 9) print(can_nest([1, 2, 3, 4], [2, 3])) # Output: False (1 is not > 2) ``` ### 4. Strict Inequality Requirement Notice the problem specifies **strictly greater** (`>`) and **strictly less** (`<`). If `max(list1) == max(list2)`, the test evaluates to `False`. ### 5. Common Mistakes - **Using <= or >=**: Using `<=` or `>=` fails when list extrema are equal. The problem requires strict boundary containment! ### 6. Congratulations! Congratulations! You have completed all 30 foundational Python Beginner Practice Learning Bytes, covering arithmetic operations, list slicing, list comprehensions, dictionary formatting, and algorithmic boundary testing!
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